toJson method

  1. @override
Map<String, Object> toJson({
  1. ClientUriConverter? clientUriConverter,
})

Returns a JSON presentation of the object.

Implementation

@override
Map<String, Object> toJson({ClientUriConverter? clientUriConverter}) {
  var result = <String, Object>{};
  result['initialProblems'] =
      initialProblems
          .map(
            (RefactoringProblem value) =>
                value.toJson(clientUriConverter: clientUriConverter),
          )
          .toList();
  result['optionsProblems'] =
      optionsProblems
          .map(
            (RefactoringProblem value) =>
                value.toJson(clientUriConverter: clientUriConverter),
          )
          .toList();
  result['finalProblems'] =
      finalProblems
          .map(
            (RefactoringProblem value) =>
                value.toJson(clientUriConverter: clientUriConverter),
          )
          .toList();
  var feedback = this.feedback;
  if (feedback != null) {
    result['feedback'] = feedback.toJson(
      clientUriConverter: clientUriConverter,
    );
  }
  var change = this.change;
  if (change != null) {
    result['change'] = change.toJson(clientUriConverter: clientUriConverter);
  }
  var potentialEdits = this.potentialEdits;
  if (potentialEdits != null) {
    result['potentialEdits'] = potentialEdits;
  }
  return result;
}