parse static method

int parse(dynamic v, { bool allowHex = true, })

Parses a dynamic value v into an integer.

Tries to convert the dynamic value v into an integer. It supports parsing from int, BigInt, List<int>, and String types. If v is a String and represents a hexadecimal number (prefixed with '0x' or not), it is parsed accordingly. allowHex: convert hexadecimal to integer Parameters:

• v: The dynamic value to be parsed into an integer.

Returns:

• An integer representation of the parsed value.

Implementation

static int parse(dynamic v, {bool allowHex = true}) {
  try {
    if (v is int) return v;
    if (v is BigInt) {
      if (!v.isValidInt) {
        throw ArgumentException("value is to large for integer.",
            details: {"value": "$v"});
      }
      return v.toInt();
    }
    if (v is String) {
      int? parse = int.tryParse(v);
      if (parse == null && allowHex && StringUtils.ixHexaDecimalNumber(v)) {
        parse = int.parse(StringUtils.strip0x(v), radix: 16);
      }
      return parse!;
    }
  } catch (_) {}
  throw ArgumentException("invalid input for parse int",
      details: {"value": "$v"});
}