dayOfYear function
Given a month and day number, return the day of the year, all one-based.
For example,
- January 2nd (1, 2) -> 2.
- February 5th (2, 5) -> 36.
- March 1st of a non-leap year (3, 1) -> 60.
Implementation
int dayOfYear(int month, int day, bool leapYear) {
if (month == 1) return day;
if (month == 2) return day + 31;
return ordinalDayFromMarchFirst(month, day) + 59 + (leapYear ? 1 : 0);
}