groupBySize<V> function

Iterable<Iterable<V>> groupBySize<V>(Iterable<V> source, int sizeEachList)

Groups the items from the list source into sub-lists of the size given in sizeEachList

Example:

final List source = [
  'Dying Light 1',
  'Dying Light 2',
  'Dead Island 1',
  'Dead Island Riptide',
  'GTA IV',
  'Batman: Arkham City GOTY',
  'F.E.A.R. 1',
  'F.E.A.R. 2',
  'F.E.A.R. 3',
];
final groupedList3 = groupBySize(source, 3);
print(groupedList3.toString());
//[
// [Dying Light 1, Dying Light 2, Dead Island 1],
// [Dead Island Riptide, GTA IV, Batman: Arkham City GOTY],
// [F.E.A.R. 1, F.E.A.R. 2, F.E.A.R. 3]
//]

Implementation

Iterable<Iterable<V>> groupBySize<V>(Iterable<V> source, int sizeEachList) {
  return source.toList().fold<List<List<V>>>([],
      (List<List<V>> value, V element) {
    if (value.isEmpty || value.last.length == sizeEachList) {
      value.add(<V>[element]);
    } else {
      value.last.add(element);
    }
    return value;
  });
}