toJson method
Convert the OpenApi object to a JSON spec representation
Implementation
Map<String, dynamic> toJson() {
if (paths == null && components == null && webhooks == null) {
throw Exception(
'\n\nOpenAPI spec must contain at least one of the following: paths, components, or webhooks\n',
);
}
Map<String, dynamic> out = {
'openapi': version,
'info': info.toJson(),
'jsonSchemaDialect': jsonSchemaDialect,
'externalDocs': externalDocs?.toJson(),
'servers': servers?.map((e) => e.toJson()).toList(),
'tags': tags?.map((e) => e.toJson()).toList(),
'paths': paths?.map((k, v) => MapEntry(k, v.toJson())),
'webhooks': webhooks?.map((k, v) => MapEntry(k, v.toJson())),
'components': components?.toJson(),
'security': security?.map((e) => e.toJson()).toList(),
};
return _formatSpecToJson(out);
}